Title
Two-pebbling and odd-two-pebbling are not equivalent.
Abstract
Let G be a connected graph. A configuration of pebbles assigns a nonnegative integer number of pebbles to each vertex of G. A move consists of removing two pebbles from one vertex and placing one pebble on an adjacent vertex. A configuration is solvable if any vertex can get at least one pebble through a sequence of moves. The pebbling number of G, denoted π(G), is the smallest integer such that any configuration of π(G) pebbles on G is solvable. A graph has the two-pebbling property if after placing more than 2π(G)−q pebbles on G, where q is the number of vertices with pebbles, there is a sequence of moves so that at least two pebbles can be placed on any vertex. A graph has the odd-two-pebbling property if after placing more than 2π(G)−r pebbles on G, where r is the number of vertices with an odd number of pebbles, there is a sequence of moves so that at least two pebbles can be placed on any vertex. In this paper, we prove that the two-pebbling and odd-two-pebbling properties are not equivalent.
Year
DOI
Venue
2019
10.1016/j.disc.2018.10.030
Discrete Mathematics
Keywords
Field
DocType
Graph pebbling,Lemke graph,Two-pebbling,Odd-two-pebbling
Integer,Graph,Discrete mathematics,Combinatorics,Vertex (geometry),Neighbourhood (graph theory),Pebble,Connectivity,Mathematics
Journal
Volume
Issue
ISSN
342
3
0012-365X
Citations 
PageRank 
References 
0
0.34
5
Authors
3
Name
Order
Citations
PageRank
Charles A. Cusack1224.89
Airat Bekmetjev2243.71
Mark Powers311.07